8x^2+54x-57=0

Solution for 8x^2+54x-57=0 equation:

8x^2+54x-57=0

a = 8; b = 54; c = -57;
Δ = b2-4ac
Δ = 542-4·8·(-57)
Δ = 4740
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4740}=\sqrt{4*1185}=\sqrt{4}*\sqrt{1185}=2\sqrt{1185}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-2\sqrt{1185}}{2*8}=\frac{-54-2\sqrt{1185}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+2\sqrt{1185}}{2*8}=\frac{-54+2\sqrt{1185}}{16}
$